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Volume of a frustum of a square pyramid = (1/3)h(a² + b² + ab) = (1/3) * 8 * (10² + 6² + 10*6) = (1/3) × 8 × (196) = (8×196)/3 = 1568/3 = 522.66 cm or 523 cm³ Answer: (C)
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