A petrol pump has a blend of 40 liters of petrol and diesel in the ratio of 5:3. After selling 16 liters of the mixture, 12 liters of petrol are added to the remaining mixture. Subsequently, 20 liters of the mixture are sold, and then 8 liters of petrol are added. What percentage of the final quantity of petrol is the final quantity of diesel?

Solution

ATQ, Petrol in 40 liters = (5/8) × 40 = 25liters Diesel in 40 liters = (3/8) × 40 = 15 liters Petrol in 16 liters = 16 × (5/8) = 10 liters Diesel in 16 liters = 16 × (3/8) = 6 liters After adding 12 liters Now Petrol quantity = 25 – 10 + 12 = 27 liters Diesel quantity = 15 – 6 = 9 liters Now the ratio of petrol and diesel= 27:9 = 3:1 petrol in 20 liters = 20 × (¾) = 15 liters Water in 20 liters = 20 × (¼) = 5 liters Final petrol quantity = 27 – 15 + 8 = 20 liters diesel quantity = 9 – 5 = 4 liters Required percentage = (4/20) × 100 = 20%