There are three mixtures A, B and C. Mixture A contains 11% of water and B contains 16% of water. If A and B are mixed together than resultant mixture contains 13% water. while If B is mixed with C, which contains 23% water so the resultant mixture contains of 19% water. All these mixture are mixed in a jar and then 37 ml water is also added. Find total volume of water preset in jar, if initially mixture C contains 69 ml water.
A B A B 11% 16% 16% 23% 13% 19% 3 2 4 3 Therefore, Ratio of mixture, A to B is 3:2 & Ratio of mixture B to C is 4:3 Hence, ratio of volume of mixtures A, B & C is A : B : C = 6 : 4 : 3 It is given that contains 23% water, which is 69 ml. Hence total volume of mixture C is 69 × (100/23) = 300 ml B is 400 ml & A is 600 ml Water in B = 16% × 400 = 64 ml Water in A = 11% × 600 = 66 ml Total water in jar after adding 307 ml water = 64 + 69 + 66 + 37 = 236 ml
