Question
A milk vendor has 93 litres of cow pure milk, 62 litres
of toned milk and 124 litres of double toned milk. If he wants to pack them in cans so that each can contains same litres of milk and does not want to mix any two kinds of milk in a can, then the least number of can required will beSolution
For least or minimum number of cans, the maximum capacity cans will be required. The maximum capacity cans for required quantity For this, we take H.C.F of given quantities H.C.F of (93 + 62 + 124) = 31 Maximum Capacity of a can = 31 litre Number of cans of cow milk = 93/31= 3 Number of cans of toned milk = 62/31 = 2 Number of cans of double toned milk = 124/31 = 4 Total number of cans = 3 + 2 + 4 = 9
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
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