Question
(a β 2) 2 + (b + 6) 2 + (c β
1) 2 = 0, then find the value of a + b β c.Solution
If (a β 2) 2 + (b + 6) 2 + (c β 1) 2 = 0, then (a = 2), (b = -6), and (c = 1).
So,
- a - 2 = 0 β a = 2
- b + 6 = 0 β b = -6
- c - 1 = 0 β c = 1
Therefore, required value:
2 + (-6) - 1 = 2 - 6 - 1 = -5
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