Question
(a β 2) 2 + (b + 6) 2 + (c β
1) 2 = 0, then find the value of a + b β c.Solution
If (a β 2) 2 + (b + 6) 2 + (c β 1) 2 = 0, then (a = 2), (b = -6), and (c = 1).
So,
- a - 2 = 0 β a = 2
- b + 6 = 0 β b = -6
- c - 1 = 0 β c = 1
Therefore, required value:
2 + (-6) - 1 = 2 - 6 - 1 = -5
(44² × 16²) ÷ (184.8 ÷ 8.4) =? × 64
If 2x+1, x+2, 2 and 5 are in proportion, then what is the mean proportional between 3.5(1-x) and 8(1+x)?
If βf + (1/βf) = 5, then find the value of f + (1/f).
48 24 24 48 ? 1536
...If (4x + 3y): (28x - y) = 1: 5, then what is the value of (3x 2 Β + 4y 2 ): (7x 2 Β + 2y 2 )?

- If a 2 Β + b 2 Β + c 2 Β = 240 and ab β bc β ca = 64, then find the value of (a + b β c) 2 .
If, 3x + y = 14, and 2xy = 32, and 3x > y, then find the value of 27xΒ³ β yΒ³.
Β
If Β x = 19 , find x 5 - 20 Β x 4 + 20 Β x 3 - 20x 2 + 20x Β - 20 = ?