Question
If {x + (1/x)} = 7, then find the value of
{x2Â - (1/x)2}.Solution
Given = {x + (1/x)} = 7 On, squaring both sides, we have; {x + (1/x)}2 = 72 Or, x2 + (1/x)2 + 2 = 49 Or, {x2 + (1/x)2} = 47 On subtracting '2' from both sides, we have; {x2 + (1/x)2 - 2} = 45 Or, {x - (1/x)}2 = 45 So, {x - (1/x)} = 3√5 Since, (a2 - b2) = (a + b) X (a - b) {x2 - (1/x)2} = {x - (1/x)} X {x + (1/x)} = 3√5 X 7 = 21√5
3Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 18Â Â Â Â Â 149Â Â Â Â Â Â Â Â 602Â Â Â Â Â Â Â Â 15057
...1, 1, 3, 15, 105, 942
- Find the wrong number in the given number series.
8, 14, 24, 49, 59, 84 2, 4, 16, 48, 240, 1440, 10080
1001, 934, 863, 790, 711, 630, 539
Find the wrong number in the given number series.
1728, 121, 1000, 729, 512, 49
Find the wrong number in the given number series.
21, 31, 11, 41, 1, 61Find the wrong number in the given number series.
548, 532, 568, 510, 604, 460
9Â Â Â Â Â Â Â Â Â Â Â Â Â 17Â Â Â Â Â Â Â Â Â Â 53Â Â Â Â Â Â Â Â Â Â 103Â Â Â Â Â Â Â Â 310Â Â Â Â Â Â Â Â 619
...43, 42, 41, 39, 33, 10