Question
If 1/(x+ 1/(y+ 1/z)) = 13/30, then find x+y+z=
?Solution
Dividing numerator and denominator of RHS by 13. ⇒ (13/13)/(30/13) = 1/(30/13) = 1/(2+ 4/13) Again dividing by 4. ⇒ 1/(2+ (4/4)/(13/4)) = 1/(2+ 1/(13/4)) ⇒ 1/(2+ 1/(3+ 1/4)) ∴ x = 2, y = 3, z = 4 ∴ x+y+z= 9
More Algebra Questions
13 19 32 52 ? 113
1290, 1225, 1175, ?, 1112, 1095, 1085
? , 864, 432, 144, 36, 7.2
106, 124, 88, 142, ?, 160
What value should come in the place of (?) in the following number series?
5670, 1620, 540, 216, 108, ?
7, 9, 21, ?, 107, 197
71, 79, 88, 152, ?, 393
14, 20, 29, 44, 65, ?
What will come in place of the question mark (?) in the following series?
2.5, 6.5, 18.5, 54.5, 162.5, 486.5, ?
22, 37, 63, 98, 148, ?
Relevant for Exams:
