Question
The ratio of age of βAβ 5 years ago from now to the age of βBβ 5 years hence from now is 4 : 7. If the sum of the present age of βAβ and βBβ is 55 years, then find the age of βBβ 3 years hence from now.
Solution
Let the present ages of βAβ and βBβ be βpβ years and βqβ years respectively. Then, p + q = 55 Or, q = 55 β p ATQ, [{(p - 5)}{(q + 5)} = {4/7}] Or, 7(p β 5) = 4(q + 5) Or, 7p β 35 = 4q + 20 Or, 7p β 4q = 55 Or, 7p β 4(55 β p) = 55 Or, 7p β 220 + 4p = 55 Or, 11p = 275 Or, p = 25 Or, q = 55 β 25 = 30 Therefore, age of βBβ 3 years hence from now = 30 + 3 = 33 years
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