Question
The ratio of age of βAβ 5 years ago from now to the
age of βBβ 5 years hence from now is 4 : 7. If the sum of the present age of βAβ and βBβ is 55 years, then find the age of βBβ 3 years hence from now.Solution
Let the present ages of βAβ and βBβ be βpβ years and βqβ years respectively. Then, p + q = 55 Or, q = 55 β p ATQ, [{(p - 5)}{(q + 5)} = {4/7}] Or, 7(p β 5) = 4(q + 5) Or, 7p β 35 = 4q + 20 Or, 7p β 4q = 55 Or, 7p β 4(55 β p) = 55 Or, 7p β 220 + 4p = 55 Or, 11p = 275 Or, p = 25 Or, q = 55 β 25 = 30 Therefore, age of βBβ 3 years hence from now = 30 + 3 = 33 years
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
(27.08)2 β (14.89)2 β (22.17)2 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
564.932 + 849.029 β 425.08 = 612.095 + ?
The monthly savings of three individuals 'P', 'Q', and 'R' are such that the average savings of 'P' and 'Q', 'Q' and 'R', and 'R' and 'P' are Rs. 2,000,...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1279.98 Γ· 40.48 Γ 10.12 = ? Γ 2.16
157.78% of 4820 + 92.33% of 2840 = ? + 115.55% of 1980
45.22% of (71.9 x 5.01) + 69.97 =?Β
24.96% of 380 + ? β 169.99 = 149.99% of 80