The average of present ages of 'Emily', 'Frank', and

Solution

ATQ, Sum of the present ages of 'Emily', 'Frank', and 'George' = 25 x 3 = 75 years. Sum of the present ages of 'Frank', 'George', and 'Harry' = (18 x 3) + (4 x 3) = 66 years. Difference between the present ages of 'Emily' and 'Harry' = 75 - 66 = 9 years. Let the present ages of 'Emily' and 'Harry' be 'e' years and 'h' years, respectively. e - h = 9 -----------(i) Sum of present ages 'E' and 'H' = 58 years. e + h = 58 ---------(ii) Adding equations (i) and (ii), we get: 2e = 67 Or, 'e' = 67 / 2 = 33.5 So, the age of 'Emily' three years ago from now = e - 3 = 33.5 - 3 = 30.5 years.