📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    The average of present ages of 'Emily', 'Frank', and

    'George' is 25 years. Four years ago, the average of ages of 'Frank', 'George', and 'Harry' was 18 years. If the sum of the present ages of 'Emily' and 'Harry' is 58 years, then what was the age of 'Emily' three years ago from now?
    A 22.6 yrs Correct Answer Incorrect Answer
    B 18.25 yrs Correct Answer Incorrect Answer
    C 30.5 yrs Correct Answer Incorrect Answer
    D 25.2 yrs Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Sum of the present ages of 'Emily', 'Frank', and 'George' = 25 x 3 = 75 years. Sum of the present ages of 'Frank', 'George', and 'Harry' = (18 x 3) + (4 x 3) = 66 years. Difference between the present ages of 'Emily' and 'Harry' = 75 - 66 = 9 years. Let the present ages of 'Emily' and 'Harry' be 'e' years and 'h' years, respectively. e - h = 9 -----------(i) Sum of present ages 'E' and 'H' = 58 years. e + h = 58 ---------(ii) Adding equations (i) and (ii), we get: 2e = 67 Or, 'e' = 67 / 2 = 33.5 So, the age of 'Emily' three years ago from now = e - 3 = 33.5 - 3 = 30.5 years.

    Practice Next
    More Age Questions

    Relevant for Exams:

    ask-question