Question
The difference between the ages of two daughters is 8
years. 12 years ago, the elder one was twice as old as the younger one. The present age of the elder daughter is:Solution
ATQ, Let the present age of the younger daughter be ( y ). Therefore, the present age of the elder daughter is ( y + 8 ). ATQ, 12 years ago, the elder one was twice as old as the younger one. We can formulate this as: [ (y + 8) - 12 = 2(y - 12) ] Solving the equation: [ y - 4 = 2y - 24 ] [ 24 - 4 = 2y - y ] [ 20 = y ] Now that we know the younger daughter’s present age (( y = 20 )), we can find the elder daughter’s age: [ y + 8 = 20 + 8 ] [ y + 8 = 28 ] So, the present age of the elder daughter is 28 years.
140Â Â Â Â 300Â Â Â Â 380Â Â Â Â Â 420Â Â Â Â Â 440Â Â Â Â Â ?
...49Â Â Â 84Â Â Â 119Â Â Â 154Â Â Â 189Â Â Â ?
5 4 29 24 185 ?
112    162    199    ?     242    252
...32Â Â Â 96Â Â Â Â 240Â Â Â Â 480Â Â Â Â Â 720Â Â Â ?
21     84      168      172     ?     348
...70    191    47    216    ?    245
16 18 14 20 12 ?
...13, 14, 18, 27, 43, ?
13Â Â Â Â Â Â Â Â Â Â 182Â Â Â Â Â Â Â Â 303Â Â Â Â Â Â Â Â 384Â Â Â Â Â Â Â Â 433Â Â Â Â Â Â Â Â ?
...
