Question
The difference between the ages of two daughters is 8
years. 12 years ago, the elder one was twice as old as the younger one. The present age of the elder daughter is:Solution
ATQ, Let the present age of the younger daughter be ( y ). Therefore, the present age of the elder daughter is ( y + 8 ). ATQ, 12 years ago, the elder one was twice as old as the younger one. We can formulate this as: [ (y + 8) - 12 = 2(y - 12) ] Solving the equation: [ y - 4 = 2y - 24 ] [ 24 - 4 = 2y - y ] [ 20 = y ] Now that we know the younger daughter’s present age (( y = 20 )), we can find the elder daughter’s age: [ y + 8 = 20 + 8 ] [ y + 8 = 28 ] So, the present age of the elder daughter is 28 years.
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Statements : P > Q < R = U ≤ V = S ≤ W ≥ X > I
Conclusions :
I. Q ≥ V
II. R ≤ W
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