Question
The average ages of A, B and C is 20% more than the
average ages of A and B. 10years hence from now, the ratio of the ages of A and C will be 3:5, respectively and age of B will be the mean of their ages at the time. Find the sum of present ages of B and C.Solution
Let the age of A and C 10 years from now we 3X years and 5X year respectively. So age of B 10 years from now = (3X+5X)/2 = 4x years. As per question (3x-10+4x-10+5x-10)/3 = 1.2*(3x-10+4x-10)/2 24x-60 = 3.6*(7x-20) 24x-60 = 25.2x-72 1.2x=12 X=10 Sum of present age of B and C = (4*10-10) +(5*10-10) = 70 years.
- Find the wrong number in the given number series.
25, 36, 29, 40, 33, 50 154Â Â Â Â 165Â Â Â Â 143Â Â Â Â 175Â Â Â Â Â 132Â Â Â Â Â 187
...5000, 4500, 3600, 2480, 1512, 756Â Â Â
Find the wrong number in the given number series,
125, 150, 250, 475, 875, 1500
- Find the wrong number in the given number series.
5, 8, 12, 19, 27, 39 768Â Â Â 2304Â Â Â 288Â Â Â 864Â Â Â 106Â Â Â 324
Find the wrong number in the given number series.
5, 6, 14, 45, 188, 925
120, 240, 80, 320, 60, 384
21 32 54 86 131 186
... 7    12     33    126    635  Â
