Question
Present ages of βAβ, βBβ and βCβ are in the
ratio 10:12:15, respectively. If present average age of βAβ and βCβ is 50 years, then find the age of βBβ when βCβ was 24 years old?Solution
Let the present ages of βAβ, βBβ and βCβ be β10xβ years, β12xβ years and β15xβ years, respectively. ATQ; (15x + 10x) Γ· 2 = 50 Or, 25x = 100 So, x = 4 So, present age of βCβ = 15 Γ 4 = 60 years Present age of βBβ = 12 Γ 4 = 48 years Difference between the ages of βBβ and βCβ = 60 β 48 = 12 years So, age of βBβ when βCβ was 24 years old = 24 β 12 = 12 years
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