Question
Present ages of ‘A’, ‘B’ and ‘C’ are in the
ratio 10:12:15, respectively. If present average age of ‘A’ and ‘C’ is 50 years, then find the age of ‘B’ when ‘C’ was 24 years old?Solution
Let the present ages of ‘A’, ‘B’ and ‘C’ be ‘10x’ years, ‘12x’ years and ‘15x’ years, respectively. ATQ; (15x + 10x) ÷ 2 = 50 Or, 25x = 100 So, x = 4 So, present age of ‘C’ = 15 × 4 = 60 years Present age of ‘B’ = 12 × 4 = 48 years Difference between the ages of ‘B’ and ‘C’ = 60 – 48 = 12 years So, age of ‘B’ when ‘C’ was 24 years old = 24 – 12 = 12 years
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