Question
Present age of βAβ is 25% more than that of βBβ.
If 15 years hence from now, βBβ will be 14 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.25 = β1.25xβ years ATQ; (x + 15) + 14 = (1.25x + 15) Or, x + 29 = 1.25x + 15 Or, 14 = 0.25x Or, x = 56 So, present age of βBβ = 56 years And, present age of βAβ = 56 + 14 = 70 years Required sum = 56 + 70 = 126 years
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