Question
Present age of βAβ is 40% more than that of βBβ.
If 11 years hence from now, βBβ will be 5 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of βBβ = 12.5 years And, present age of βAβ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
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