Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 5 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
- Identify x such that x% of 540 plus {1080 ÷ x of 9} × 6 gives 162
360 × 9 ÷ 3 + 120 + 900 ÷ 5 = ?
2350 – 4830 + 9570 + 3350 – 1720 = ?
12.5% of 384 - 16.66% of 66 = √16 + √? + 22
What will come in the place of question mark (?) in the given expression?
? = 60% of 48% of (20 × 350) + 180
What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) ÷ 15 X ? = 36 X 30
Find the simplified value of the given expression:
What is the value of 7/9-11/12+12/16-1/8?
48 ÷ 6 × √25 + 13 × 8 = ?
What will come in the place of question mark (?) in the given expression?
(308 – 154) ÷ 11 = ? ÷ 15
