Question
βBβ is 8 years elder to βAβ who is 20 years
younger to βCβ. Eight years hence from now, age of βCβ will be 25% more than that of age of βAβ. If average of present ages of βAβ and βDβ is 60 years, then find the ratio of ages of βBβ to βDβ, 10 years ago from now.Solution
Let present age of βCβ is βxβ years. Present age of βAβ = βx β 20β years Present age of βBβ = x β 20 + 8 = βx β 12β years So, 1.25 Γ (x β 20 + 8) = x + 8 => 1.25 (x β 12) = x + 8 =>1.25x β 15 = x + 8 => 0.25x = 23 => x = 92 Present age of βBβ = 92 β 12 = 80 years Present age of βDβ = 60 Γ 2 β 72 = 48 years Desired ratio = (80 β 10):(48 β 10) = 70:38 = 35:19
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