Question
‘B’ is 8 years elder to ‘A’ who is 20 years
younger to ‘C’. Eight years hence from now, age of ‘C’ will be 25% more than that of age of ‘A’. If average of present ages of ‘A’ and ‘D’ is 60 years, then find the ratio of ages of ‘B’ to ‘D’, 10 years ago from now.Solution
Let present age of ‘C’ is ‘x’ years. Present age of ‘A’ = ‘x – 20’ years Present age of ‘B’ = x – 20 + 8 = ‘x – 12’ years So, 1.25 × (x – 20 + 8) = x + 8 => 1.25 (x – 12) = x + 8 =>1.25x – 15 = x + 8 => 0.25x = 23 => x = 92 Present age of ‘B’ = 92 – 12 = 80 years Present age of ‘D’ = 60 × 2 – 72 = 48 years Desired ratio = (80 – 10):(48 – 10) = 70:38 = 35:19
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
