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    Question

    β€˜B’ is 8 years elder to β€˜A’ who is 20 years

    younger to β€˜C’. Eight years hence from now, age of β€˜C’ will be 25% more than that of age of β€˜A’. If average of present ages of β€˜A’ and β€˜D’ is 60 years, then find the ratio of ages of β€˜B’ to β€˜D’, 10 years ago from now.
    A 32:19 Correct Answer Incorrect Answer
    B 33:19 Correct Answer Incorrect Answer
    C 35:19 Correct Answer Incorrect Answer
    D 30:19 Correct Answer Incorrect Answer
    E 35:32 Correct Answer Incorrect Answer

    Solution

    Let present age of β€˜C’ is β€˜x’ years. Present age of β€˜A’ = β€˜x – 20’ years Present age of β€˜B’ = x – 20 + 8 = β€˜x – 12’ years So, 1.25 Γ— (x – 20 + 8) = x + 8 => 1.25 (x – 12) = x + 8 =>1.25x – 15 = x + 8 => 0.25x = 23 => x = 92 Present age of β€˜B’ = 92 – 12 = 80 years Present age of β€˜D’ = 60 Γ— 2 – 72 = 48 years Desired ratio = (80 – 10):(48 – 10) = 70:38 = 35:19

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