Question
The ratio of the present ages of βAβ and βBβ is
5:7, respectively. Three years hence from now, the age of βBβ will be 17 years. If the average of present ages of βAβ, βBβ and βCβ is 18 years, then find the present age of βCβ.Solution
Let the present ages of βAβ and βBβ be 5x years and 7x years, respectively Therefore, 7x + 3 = 17 Or, 7x = 14 Or, x = 2 Sum of present ages of βAβ and βBβ = 5x + 7x = 24 years Sum of present ages of βAβ, βBβ and βCβ = 18 Γ 3 = 54 years Therefore, present age of βCβ = 54 β 24 = 30 years
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