Question
A is five times as old as B. C was twice-as old as A six
years ago. In six years' time, A will be 31. Find the sum of the present ages of B and C.Solution
Let the age of A = A, B = B and C = C According to question, => A = 5B 6 years ago, => C - 6 = 2(A - 6) After 6 years, => A + 6 = 31 => A = 25 So, B = 25/5 = 5Â => C = 2(A - 6) + 6 => C = 2(25 - 6) + 6Â => C = 38 + 6 = 44 Sum of the present ages of B and C = 5 + 44 = 49 years
Six boxes, T, U, V, W, X and Y are kept one above the other (not necessarily in the same manner). There are four box between T and U. There are two boxe...
Find the odd one out.
Four of the following five form a group as per the given arrangement. Which of the following does not belong to that group?
The person whose age is third highest works for which company?
Which of the following two persons visit Mumbai?
What is the difference between the floor number of M and T?
Who visits just before the one who has White?
How many boxes are kept between box X and the box which contains Pencil?
How many people have birthdays before S?
On which date is Sunday?
