Question
A is five times as old as B. C was twice-as old as A six
years ago. In six years' time, A will be 31. Find the sum of the present ages of B and C.Solution
Let the age of A = A, B = B and C = C According to question, => A = 5B 6 years ago, => C - 6 = 2(A - 6) After 6 years, => A + 6 = 31 => A = 25 So, B = 25/5 = 5Â => C = 2(A - 6) + 6 => C = 2(25 - 6) + 6Â => C = 38 + 6 = 44 Sum of the present ages of B and C = 5 + 44 = 49 years
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