Question
The present age of A is 8/3 times to that of his
marriage age. Present age of his brother is 1/4th of his present age. If A was married 40 years ago then find the present age of his brother.Solution
Let the age of A when he was married be x years. Present age of A = 8x/3 Present age of his brother = (1/4) × (8x/3) = 2x/3 According to Question, => x + 40 = 8/3x => 5/3x = 40 => x = 24 years Present age of his brother = (2/3) × 24 = 16 years
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