Question

Which SQL expression correctly returns employees whose salary is greater than the average salary of all employees?

A SELECT * FROM Employee WHERE Salary>AVG(Salary);
B SELECT * FROM Employee WHERE Salary>(SELECT AVG(Salary) FROM Employee);
C SELECT * FROM Employee HAVING Salary>AVG(Salary);
D SELECT * FROM Employee GROUP BY Salary WHERE Salary>AVG(Salary);
E SELECT * FROM Employee WHERE Salary>SELECT AVG(Salary) FROM Employee;
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