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    Question

    If 2 K bits/second is bit rate, what is the minimum PCM

    bandwidth required for successful transmission?Β 
    A 8 KHz Correct Answer Incorrect Answer
    B 4 KHz Correct Answer Incorrect Answer
    C 1 KHz Correct Answer Incorrect Answer
    D 2 KHz Correct Answer Incorrect Answer

    Solution

    In Pulse Code Modulation (PCM), the minimum bandwidth required is equal to half of the bit rate (Nyquist criterion). Bit rate = 2 Kbits/s
    Β  Minimum bandwidth = Bit rate / 2 = 2000 / 2 = 1000 Hz = 1 kHz

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