Question
If 2 K bits/second is bit rate, what is the minimum PCM
bandwidth required for successful transmission?ÂSolution
In Pulse Code Modulation (PCM), the minimum bandwidth required is equal to half of the bit rate (Nyquist criterion). Bit rate = 2 Kbits/s
 Minimum bandwidth = Bit rate / 2 = 2000 / 2 = 1000 Hz = 1 kHz
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Fill in the blank/s with suitable Word/s:
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