Question

Given a table Employees(EmpID, ManagerID, Salary), which SQL statement correctly returns the EmpID of every employee who earns strictly more than their direct manager?

A SELECT e.EmpID FROM Employees e, Employees m WHERE e.ManagerID = m.ManagerID AND e.Salary > m.Salary;
B SELECT e.EmpID FROM Employees e LEFT JOIN Employees m ON e.EmpID = m.ManagerID WHERE e.Salary > m.Salary;
C SELECT e.EmpID FROM Employees e JOIN Employees m ON e.EmpID = m.ManagerID WHERE e.Salary > m.Salary;
D SELECT e.EmpID FROM Employees e JOIN Employees m ON e.ManagerID = m.EmpID WHERE e.Salary > m.Salary;
E SELECT e.EmpID FROM Employees e WHERE e.Salary > (SELECT AVG(Salary) FROM Employees m WHERE m.ManagerID = e.ManagerID);
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