Question
Which of the following synchronization techniques is
used to resolve the Readers-Writers Problem efficiently?Solution
Semaphores are synchronization primitives used to manage access to shared resources in multi-threaded environments. In the Readers-Writers Problem, semaphores efficiently balance multiple readers accessing shared data simultaneously, while ensuring mutual exclusion for writers to avoid data inconsistency. The problem is solved using two semaphores: one for mutual exclusion (ensuring only one writer or a group of readers access the data) and another for resource access control. This ensures fairness and prevents issues like starvation of writers. Semaphores are widely used due to their flexibility and efficiency in solving synchronization problems. Why Other Options Are Incorrect: 1. Mutex Locks: Enforce strict mutual exclusion but cannot differentiate between readers and writers, leading to inefficiency. 2. Spinlocks: Suitable for short wait times but consume CPU cycles unnecessarily, making them inefficient. 3. Monitors: Provide higher-level synchronization but require language-level support, limiting their applicability. 4. Condition Variables: Complement mutexes but are not standalone synchronization mechanisms. Semaphores provide an optimal balance of efficiency and simplicity for resolving the Readers-Writers Problem.
A takes 3 hours more while swimming upstream than downstream. His speed in still water is 12 km/hr. The speed of stream is 4 km/hr. What is the distance?
The ratio of the speed of boats βAβ and βBβ in still water is 8:9, respectively. The speed of the current is 25% of the speed of boat βAβ in...
- A boat covers 90 km downstream and 70 km upstream in a total time of 10 hours. How much time will it take to travel 126 km downstream and 98 km upstream?
A boat takes 3 hours 45 minutes to cover 67.5 km in downstream. The ratio of the speed of the boat in still water to the speed of the stream is 5:1. Fin...
Speed of a boat in still water is three times the speed of the boat in upstream. If the boat takes 30 minutes to cover 27 km in downstream, then find th...
A man rows x km downstream and the same distance upstream in 16 hours. He can row 8x km downstream in 16 hours. How long will he take to row x km upstream?
The speed of the stream is 12 km/h. Boat βAβ covers 100 km distance against the stream in 5 hours and boat βBβ covers 80 km distance against the...
A boat moving upstream takes 8 hours 48 minutes to cover a distance while it takes 4 hours to return to the starting point, downstream. What is the rati...
Boat βAβ can cover 150 km in still water in 15 hours. In still water, if the ratio of the speed of boat βAβ to that of βBβ is 5:1 and the sp...
The ratio of the speed of boat βAβ in still water, the speed of boat βBβ in still water and the speed of the current is 7:4:2, respectively. If ...