Question

In C++, a base class pointer holds the address of a derived class object. The base class declares a non-virtual member function that the derived class redefines (not overrides) with the same signature. When this function is called through the base class pointer, which version executes?

Q: Answer-In C++, a base class pointer holds the address of a derived class object. The base class declares a...

Non-virtual member functions in C use static compile-time binding, resolved according to the declared type of the pointer or reference used to make the call not the actual type of the object it points to. Since the pointer is declared as the base class type, the base classs version of the function is invoked, regardless of what derived object it actually points to. Only virtual functions use dynamic runtime dispatch based on the objects actual type.

A The derived class's version executes, because C++ always resolves member function calls based on the object's actual runtime type

B A compile-time error occurs, because redefining a non-virtual function in a derived class without the override keyword is prohibited

C The base class's version executes, because calls to non-virtual functions are resolved at compile time using the pointer's static, declared type

D The behavior is undefined, because mixing virtual and non-virtual function semantics through a base pointer violates the C++ standard

E The derived class's version executes, but only if the base class function was declared inline; otherwise the base version runs

Practice Next

In C++, a base class pointer holds the address of a derived class object. The base class declares a non-virtual member function that the derived class redefines (not overrides) with the same signature. When this function is called through the base class pointer, which version executes?

Detailed Solution

More C Programming Questions

Hey! Ask a query

Please Register/Login

RBI Grade B 2026 Phase 1 Memory Based Paper