ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!

    Question

    What will be the output of the following code snippet

    demonstrating abstraction in Python? from abc import ABC, abstractmethod class Shape(ABC): ┬а ┬а @abstractmethod ┬а ┬а def area(self): ┬а ┬а ┬а ┬а pass class Circle(Shape): ┬а ┬а def __init__(self, radius): ┬а ┬а ┬а ┬а self.radius = radius ┬а ┬а def area(self): ┬а ┬а ┬а ┬а return 3.14 * self.radius * self.radius circle = Circle(5) print(circle.area())
    A 3.14 Correct Answer Incorrect Answer
    B 31.4 Correct Answer Incorrect Answer
    C 78.5 Correct Answer Incorrect Answer
    D 25 Correct Answer Incorrect Answer
    E TypeError Correct Answer Incorrect Answer

    Solution

    In the given code snippet, an abstract base class Shape is defined with an abstract method area. The Circle class inherits from Shape and implements the area method, which calculates the area of a circle using the formula ╧Аr2\pi r^2╧Аr2. When the Circle instance with a radius of 5 is created, calling circle.area() computes the area as 3.14├Ч5├Ч5=78.53.14 \times 5 \times 5 = 78.53.14├Ч5├Ч5=78.5. Therefore, the output is 78.5. Why Other Options Are Wrong: A) 3.14: This option is incorrect because it only represents the value of ╧А, not the computed area. B) 31.4: This option is incorrect as it suggests a miscalculation of the area, possibly interpreting it as ╧А multiplied by the radius. D) 25: This option is incorrect because it reflects the square of the radius (5), not the area. E) TypeError: This option is incorrect because there is no type error; the code correctly implements abstraction and executes without issues.

    Practice Next
    More Basics of Computers Questions

    Relevant for Exams:

    ask-question