Question
Given the following code snippet implementing a Round
Robin CPU scheduling algorithm, what will be the output when the processes are scheduled? def round_robin(processes, burst_time, quantum):   n = len(processes)   waiting_time = [0] * n   remaining_time = burst_time[:]   t = 0   while True:     done = True     for i in range(n):       if remaining_time[i] > 0:         done = False         if remaining_time[i] > quantum:           t += quantum           remaining_time[i] -= quantum         else:           t += remaining_time[i]           waiting_time[i] = t - burst_time[i]           remaining_time[i] = 0     if done:       break   return waiting_time processes = [1, 2, 3] burst_time = [10, 5, 8] quantum = 2 waiting_time = round_robin(processes, burst_time, quantum) print(waiting_time)Solution
The Round Robin scheduling algorithm allocates a fixed time quantum to each process. In the given example, three processes have burst times of 10, 5, and 8, respectively. With a time quantum of 2, each process is executed in turn until all are completed. The waiting times for each process are calculated as follows: • Process 1: Waiting time = Total time elapsed - Burst time = 20 - 10 = 12 • Process 2: Waiting time = 5 - 5 = 3 • Process 3: Waiting time = Total time elapsed - Burst time = 20 - 8 = 6 Thus, the output is [12, 3, 6]. Why Other Options Are Wrong: B) [14, 5, 8]: This option is incorrect as it does not accurately reflect the waiting times computed in the Round Robin scheduling. C) [10, 2, 4]: This option is incorrect because it implies significantly lower waiting times than calculated. D) [9, 1, 2]: This option is incorrect as it underestimates the waiting times based on the execution order. E) [0, 0, 0]: This option is incorrect as it assumes no waiting time at all, which is not the case.
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