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Borrowing 2 bits from the host portion of the IP address increases the number of subnet bits from 24 to 26 (since the original mask is /24). With 2 bits for subnets, 22=42^2 = 422=4 subnets can be created. The new subnet mask will be 255.255.255.192 (or /26), which leaves 6 bits for the host portion, allowing 64 addresses per subnet (with 62 usable addresses). Why Other Options are Incorrect: A) 2 subnets, 255.255.255.128: Borrowing only 1 bit from the host portion would create 2 subnets, but the question specifies borrowing 2 bits. C) 6 subnets, 255.255.255.224: This option provides an incorrect number of subnets based on the number of bits borrowed. D) 8 subnets, 255.255.255.240: Borrowing 3 bits would yield 8 subnets, not 4. E) 16 subnets, 255.255.255.248: Borrowing 4 bits would create 16 subnets, which is beyond the scope of this question.
(5⁴) 5 × (25³)³ = ?
What will come in place of a?
(6)1.2 × (216 )2.7 × (36)2.7 = 6a
If (5000) 5 = 3.125
If √35 = 5.9 find the value of
(1.69) -1.5 = ?
If √7 × √35 = x√5, then find the value of x
Find the value of 56× 59÷ 514= ?
What is least number which when successively divided by 6, 4 and 4 leaves a remainder 5, 3 and 3 respectively?
(3125) -3/5 = ?
3√4913+ 3√4.913 + 3√0.004913 = ?