Question
A wire loop in the shape of a square of side a carries
a current I. If an infinitely long straight wire carrying the same current passes through the center perpendicular to the plane of the loop, what is the net force on the loop?Solution
Given:
- A square current loop of side a carrying current I
- An infinitely long straight wire, also carrying current I, passes perpendicularly through the center of the square loop
- Both currents are in the same direction
- We are to find the net force on the loop
- The infinitely long wire creates a magnetic field around it.
- The square loop is placed symmetrically around the wire (the wire passes through its center).
- Each segment of the loop experiences a magnetic force due to the field created by the central wire.
- The magnetic field around the wire follows circular paths (right-hand rule).
- The force on each side of the loop depends on:
- Direction of the magnetic field at that location
- Direction of current in that segment
- The forces on opposite sides of the square loop are equal in magnitude but opposite in direction.
- Therefore, horizontal and vertical components of forces on opposite sides cancel each other out.
- While individual sides of the loop experience non-zero forces, the vector sum of all forces is zero.
- Hence, the net force on the square loop is zero.
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