Question
Two long parallel conductors are placed 8mm apart from
each other carrying a current of 120 Amperes. What will be force per meter length of each one?Solution
We know the force per unit length between the two conductors is F/l = μ0I1I2/2πd Here d = distance = 8 × 10-3 meter μ = 4π × 10-7 F/m And currents I1 = I2 = 120 Ampere Therefore, F/l = (4π × 10-7 × 120 × 120)/(2π × 8 × 10-3) = 0.18 N/m
351Â Â Â 261Â Â Â 181Â Â Â 111Â Â Â 51Â Â Â ?
Find the 31st term of the series 25, 29, 33……
632, 560, 494, 434, ?, 332
1331      1000            729       512       ?             216
...2556   636    156    ?    6
3 5 15 75 1125 ?
...1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
73920, 9240, ?, 220, 44, 11
12 78 385 ? 4629 9260
...A number series is given below, which follows a specific pattern. If 'A' represents the 'x'th term and 'B' represents ...
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