Two long parallel conductors are placed 8mm apart from each other carrying a current of 120 Amperes. What will be force per meter length of each one?
We know the force per unit length between the two conductors is F/l = μ0I1I2/2πd Here d = distance = 8 × 10-3 meter μ = 4π × 10-7 F/m And currents I1 = I2 = 120 Ampere Therefore, F/l = (4π × 10-7 × 120 × 120)/(2π × 8 × 10-3) = 0.18 N/m
56. 23Â Â Â Â Â 45Â Â Â Â Â 89Â Â Â Â Â 177Â Â Â Â Â 363Â Â Â Â Â 705
...Given below are three series I, II and III. Each series consist an odd one out number. Odd one out number in series I, II and III are 'P', 'Q' and 'R',...
0 2 6 12 20 ?
...3Â Â Â Â Â Â Â Â Â Â Â Â Â Â 25Â Â Â Â Â Â Â Â Â Â Â 173Â Â Â Â Â Â Â Â Â 1041Â Â Â Â Â Â Â 5201Â Â Â Â Â Â Â 20809
10       a Â...
42Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 43Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 46Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
299, 302, 308, 317, ?, 344
24, 12, 18, ?, 157.5, 708.75
35.25 71 146 296 624 1376
...315 146 267 ? 235 210
3, 4, 10, 33, 136, ?, 4116