Question
A constant retarding force of 60 N is applied to a body
of mass 25 kg moving initially with a speed of 12 m s–1. How long does the body take to stop?Solution
Given that Retarding force, F = – 60 N Mass of the body, m = 25 kg Initial velocity of the body, u = 10 m/s2 Final velocity of the body, v = 0 Using Newton’s second law of motion, the retardation (a) produced in the body can be calculated as: F = ma – 60 = 25 × a ∴ a = −60/25 a = − 2.4 m/s2 Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as v = u + a t Therefore, t = -u/a = -12/-2.4 = 5 sec
Post discontinuation of LIBOR, the RBI has proposed to revise the all-in-cost ceiling for ECBs to _______
Weighted average Cost of capital for Lavi Ltd. is 12%. Lavi Ltd. has issued equity worth Rs. 45 lakhs, 5% debt worth Rs. 15 lakhs and 6% preference sha...
An examination of a company's financial records to derive evidence which can be used in a court of law or legal proceeding is known as ________
Which of the following methods is not a method of quantitative control by RBI?
Under the Indian Trusts Act, 1882, when does the beneficiary's interest in the trust property vest? Â
Which segment of the debt markets has highest market capitalization?
Find the incorrect option regarding the elasticity of commodities?
What is the main goal of Organizational Behavior (OB)?
Deferred Tax Liabilities’ is shown under which of the following heads in a Balance sheet as per the format given in Companies Act, 2013?Â
The cost of an asset on 01-01-2002 is 5,00,000 and its life is 10 years with salvage value is zero. If it is sold on 31-12-2008 for 50,000 than calculat...
Relevant for Exams:
