Question
An electric dipole of length 10 cm, when placed with its
axis making an angle of 30° with a uniform electric field, experiences a torque of 2√3 Nm. Calculate the potential energy of the dipole, if it has a charge of ±2 nC.Solution
Torque experienced at this point (τ) = 2√3Nm The angle at which the dipole is placed θ = 30° Torque on the dipole, τ = PEsinθ Potential energy of the dipole, U = −PEcos(θ) U/ τ =−{PEcos(θ)}/{PEsinθ) Since, U = −τcotθ = - 2√3 × √3 = - 6 J
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