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    Question

    An electric dipole of length 10 cm, when placed with its

    axis making an angle of 30° with a uniform electric field, experiences a torque of 2√3 Nm. Calculate the potential energy of the dipole, if it has a charge of ±2 nC.
    A - 5 J Correct Answer Incorrect Answer
    B - 6 J Correct Answer Incorrect Answer
    C - 3 J Correct Answer Incorrect Answer
    D - 9 J Correct Answer Incorrect Answer

    Solution

    Torque experienced at this point (τ) = 2√3Nm The angle at which the dipole is placed θ = 30° Torque on the dipole, τ = PEsinθ Potential energy of the dipole, U = −PEcos(θ) U/ τ =−{PEcos(θ)}/{PEsinθ) Since, U = −τcotθ = - 2√3 × √3 = - 6 J

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