Question
Two blocks of unequal mass are connected by a string and
placed on a smooth horizontal surface. A force F is applied on the heavier block. The tension in the string is:Solution
When two blocks of unequal mass are connected by a string and placed on a smooth horizontal surface (i.e., no friction), and a force F is applied to the heavier block , both blocks accelerate together as a system. Let: • M1 be the heavier block (force is applied here), • M2 be the lighter block, • F is the total force applied on M1, • a is the common acceleration, • T is the tension in the string. Tension in the string pulls the lighter block forward. So, for lighter block:
Thus, the tension is only a part of F , used to accelerate the lighter block. It is less than F because the entire force F is used to accelerate both blocks, not just one.
234.19 ÷ 17.92 - 12.19 × 7.5 + 44.92% of 119.96 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
486, 162, 51, 18, 6, 2
√ ({(5.5 × 2.3) × √ (728.91))} = 3(1/7) ÷ ?/28
...- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
24.99% of 1619.78 + (1259.84 ÷ 12.24) = ? × 16.98
What approximate value will replace the question mark (?) in the following?
√25...
What approximate value will replace the question mark (?) in the following?
? + 3...