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When a body is thrown vertically upward, it moves against gravity, gradually slowing down due to the constant downward acceleration caused by gravity (g). As it rises, its upward velocity decreases until it reaches zero at the highest point. This is the turning point where the object changes direction from upward to downward. However, acceleration due to gravity continues to act throughout the motion , including at the peak, pulling the object downward with a magnitude of approximately 9.8 m/s². Therefore, at the highest point, the body has zero instantaneous velocity but non-zero acceleration (equal to g downward), which causes it to begin descending right after.
If A and B are complementary angles, then the value of-
sin A cos B + cos A sin B – tan A tan B + sec 2
In ∆ABC, AB = 5cm, BC = 6cm and AC = 10cm then find out the value of cos A?
If sin θ = 3/5 and cos θ = 4/5, find the value of (2tan² θ + 3cot² θ).
If 2x = cosec @ and 4/x = cot @ then the value of 2(x ² - 1/x ² ) is
Find the value of sin(θ) if 2sinθ = tanθ, for 0 < θ < 90°.
If (sinx + siny) = a and (cosx + cosy) = b, then find the value of (sinx siny + cosx cosy).
[A] (a²+b²-2)/ 2
[B] (a2-b2<...
if a sin 45 ˚ = b cosec 60 ˚ then find the value of a⁴/b⁴
...If sinAo = (√3/2), then find the value of (sin245o + cos230o) × A ÷ 5 given that 0 < A < 90...