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Weight of a body depends on the force of gravity acting upon it. In a lift stationary or moving with uniform speed (not with acceleration) the apparent weight of body is equal to its true weight. Because here the weight will be calculated as. m{g-(a)}, where m is the mass of body g is the acceleration produced due to force of gravity which is 9.8m/s² and a would be the acceleration due to the movement of lift. With uniform speed movement, the acceleration due to lift would be 0 here. Hence , option C is correct.
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