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Homi J. Bhabha was the eminent scientist who played a key role in the development of the Indian atomic energy program. He is also considered as the father of India's nuclear program. He also established the Atomic Energy Commission of India in 1948.
Simplify (cos13°+sin 13°) /(cos13°-sin13°)
If sin 23° = `12/13` , then tan 67° = ?
...Simplify: sin (A + B) sin (A - B)
If sinAo = (√3/2), then find the value of (sin245o + cos230o) × A ÷ 5 given that 0 < A < 90...
[(sinx – 2sin 3 x)/(2cos 3 x – cosx)] 2 + 1, x ≠45 o , is equal to:
If tanθ = x then find the value of cos 2θ?
