Question
Chandragupta Maurya defeated Seleucus in which
year?Solution
Chandragupta Maurya defeated Seleucus I Nicator during the Seleucid-Mauryan War, which occurred between 305 BCE and 303 BCE. The war concluded in 303 BCE with a peace treaty. According to the terms of the treaty: • Seleucus ceded several territories, including parts of Kamboja, Gandhara, and Balochistan, to Chandragupta Maurya. • Seleucus also offered a Macedonian princess in marriage to Chandragupta, symbolizing diplomatic relations. Thus, the correct answer is (c) 305 BC.
The volume of a hemisphere is 2425 (1/ 2) cm3. Find its diameter (Take p = 22/7)
The length and breadth of a rectangle are increased by 35% and 40% respectively. The increase in the area of the resulting rectangle will be:
The difference between the area of a circle and the area of the rectangle is 290.16 cm2. If the length of rectangle is 25% more and breadth i...
If the circumference of a circle is 154 cm then find the area of the circle?
- A square has a side length equal to the radius of a circle whose area is 201.96 m². Calculate the perimeter of the square.
Few people dive in a swimming pool of dimensions 25 × 15m. Due to this the water level rises by 4m. If one person displace 2 cubic metre of water. Find...
In a rectangular floor of length and breadth of 20 metres and 10 metres, respectively, square tiles each of 2 metre edge length are to be laid. If the c...
The sum of the perimeters of a square and a rectangle is 120 metres. If the sum of the length and breadth of the rectangle is 32 cm, then find the area ...
The circumference of two circles are 132 cm and 88 cm respectively. What is the difference between the area of the larger circle and the smaller circle?
