Question
The different colours of different stars are due to the
variation of –Solution
Shortly after blackbody radiation was understood, it was noticed that the spectra of stars look extremely similar to blackbody radiation curves of various temperatures, rangingfroma few thousand Kelvin to ~50,000 Kelvin. The obvious conclusion is that stars are similar to blackbodies, and that the colour variationofstarsisadirectconsequenceoftheir surface temperatures.
I. 6x² - 49x + 99 = 0
II. 5y² + 17y + 14 = 0
- Determine the value of m so that the equation x² + mx + 25 = 0 has equal and real roots.
I. 7x² + 52x + 21 = 0
II. 6y² + 7y - 24 = 0
If ‘y1’ and ‘y2’ are the roots of quadratic equation 5y2 – 25y + 15 = 0, then find the quadratic equation whose roots are ‘3y1�...
I. 2x² + 11x + 12 = 0
II. 2y² + 19y + 45 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
I. 5x2 – 18x + 16 = 0
II. 3y2 – 35y - 52 = 0
If 3x – 2y = 10 and xy = 11, the value of 27x³ – 8y³ is __________.
The nth term of a sequence is n² + 3n + 1. Find the difference between the 20th and 10th terms.
If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
