Question
A man can do a work in 20 days and a woman can do the
same work in 30 days. In how many days will 2 men and 3 women do the work?Solution
LCM (20, 30) = 60 Let the total work be the LCM of the time taken by the individuals. Hence, the total work = 60 units Efficiencies, 1 man does each day = 60 / 20 = 3 units 1 woman do each day = 60/30 = 2 units Time taken by the mentioned workforce to finish the work = 60 /(2×3+3x2) = 5 days
15% of 1800 + 22 = ?Β
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
- What will come in place of the question mark (?) in the following questions?
(2β΄ + 6Β²) Γ· 2 = ? 4/5 + 6/7 × 14/42 ÷ 24/35 = ?
What will come in the place of question mark (?) in the given expression?
45% of (β6400 Γ 5) = ? + 111Β
If 1.123 Γ 3.211 = 3.122 + ______________, then the number in blank space is
Simplify and express as a fraction in simplest form:
0.75 + 0.4 β 0.125
- What will come in the place of question mark (?) in the given expression?
389 + 641 - ? = 180 X 2 15.8% of 9000 + 20.4% of 7500 = 30% of ?
2.4 of 7.2 of 1/57.6 of 4200 = ?