Question
The perimeter of a square is equal to the perimeter of a
rectangle of length 56 cm and breadth 42 cm. Find the perimeter of a semicircle (in cm) whose diameter is equal to the side of the square (Use π = 22/7)Solution
Perimeter of a rectangle = 2(56 +42) =196 cm = perimeter of a square = 196 cm 4 x side of a square = 196 cm side of a square = 49.cm diameter of semicircle =49 cm 2r= 49 cm r= 49/2 cm Perimeter of a semi-circle = πι +2r = (22/7 x 49/2) + 2 x 49 = (77+49) = 126 cm. The perimeter of a semi- circle is 126 cm.
The questions below are based on the given Series-I. The series-I satisfies a certain pattern, follow the same pattern in Series-II and answer the ques...
4 5.5 19 .5 98.5 694 6251.5
...42 43 46 ...
203, 223, 198, 218, ?, 213
400 596 452 552 488 524
100 a �...
111 113 117 120 ? 133
85 135 172 ? 215 225
There are 3 series, you have to find value of a, b, c and then establish relation among a,b,c.
19, 25, 45, a, 553, 2767
1560 760 360 160 6...
5 13 36 145 719 4321
84, 61, 80, 57, 76, ?
