tanA = 3/4 tanA = Perpendicular/Base = 3/4 Now, SinA = Perpendicular/Hypotenuse... equation 1 Thus, Hypotenuse = √(4)2 + (3)2 √16 +9 = √25 =5 Hypotenuse = 5 From Equation 1) we get SinA = p/h = 3/5
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