Question
Container X contains a mixture of oil and water in the
ratio 1 : 3, whereas container Y contains a mixture of oil and water in the ratio 2 : 3. If 2 litres of liquid from container X and 5 litres of liquid from container Y are mixed together in container Z that initially contains 1 liter of pure oil, then what is the percentage of oil in container Z?Solution
Ratio of oil and water in container X = 1:3 Ratio of oil and water in container Y = 2:3 2 liter of mixture is taken out from X, Therefore, Oil = 2 × 1/4 = 1/2 liter Water = 2 × 3/4 = 3/2 liter Now, 5 liter of mixture is taken out from Y Therefore, Oil = 5 × 2/5 = 2 liter Water = 5 × 3/5 = 3 liter Now, In container Z, Quantity of oil = 1/2 + 2 + 1 = 7/2 liter Quantity of water = 3/2 + 3 = 9/2 liter Therefore, Required% = {(7/2)/(7/2 + 9/2)} × 100 = 7/2 × 2/16 × 100 = 175/4 = 43.75%
What will come in the place of question mark (?) in the given expression?
?% of 2480 + 15 × 34 = 1440
(82 + 62 ) × 1.25 + 20% of 145 = ? – 40% of 65Â
Evaluate: (768÷16)×(125÷25)−(81÷9)×12
What will come in place of (?) in the given expression.
40% of (120 + 80) + 25% of 160 = ?What value should come in the place of (?) in the following questions?
(3√1728 * 25) ÷ 3 * ? = 250 + 50* 3
What will come in the place of question mark (?) in the given expression?
65% of 900 - 45% of 600 = ? X 3Â
- What will come in the place of question mark (?) in the given expression?
?² = 28% of 35% of 4500 Simplify the expression:
(9x² - 25) / (3x + 5)
[{(3 × 54 × 21)/63} + 6] / 6 = √?Â
3.2% of 500 × 2.4% of ? = 288
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