Question
The digits of a two-digit number ‘N’ are
reversed to form a new number ‘M’. If M < N and N – M = 54, then which of the following maybe ‘N’?Solution
ATQ; Let the original number = N = ‘10a + b’ So, the new number = M = ‘10b + a’ ATQ; N = M + 54 So, 10a + b = 10b – a + 54 Or, 9a – 9b = 54 Or, a – b = 6 So, possible pairs of ‘a’ and ‘b’ = (9, 3), (8, 2), (7, 1) So, possible values of ‘N’ = 93, 82, 71 Alternate Solution From option ‘a’: N = 39 So, M = 93 Since, M > N {not possible} N = 71 So, M = 17 Also, N – M = 71 – 17 = 54
A-5, A, 35, 52, 78, 115
Find the wrong number in the given number series.
740, 725, 680, 605, 595
174 180 198 252 414 910
Find the wrong number in the given number series.
25, 38, 53, 74, 97, 126
Find the wrong number in the given series.
46, 104, 184, 404, 760, 1586
3 6 18 149 602 15057
...23, 36, 75, 140, 233, 348
21 32 54 86 131 186
...Find the wrong number in the given number series.
8, 16, 24, 32, 32, 64
Find the wrong number in the given number series.
8, 9, 64, 25, 216, 49
Relevant for Exams:
