Question
Find the smallest number of five digits which when
divided by 15, 30, 38, 40 respectively always leaves 2 as remainder.Solution
ATQ, Let the LCM of 15, 30, 38, and 40 is = 2280 (Least Common Multiple) TO find the smallest five-digit number in the form: N=2280k+2 We need N ≥ 10000. Solve for k: 2280k≥9998 k = 5 (smallest integer) To find N: N=2280×5+2=11402
Things done in private defence ___________________
Application for anticipatory bail may be made before:
Which of the following is not a right of consumer ?
Which of the following best describes the principle of ‘Wednesbury Unreasonableness’?
What are not included in Indian currency as per the FEMA Act, 1999?
The goods which form subject matter of sale
What are the responsibilities of the bailor regarding faults in the goods bailed as per the Contract Act?
According to John Austin the proper subject-matter of study of Jurisprudence is?
What does property mean as per section 2(jb) of the Recovery of Debts Due to Banks and Financial Institutions Act, 1993?
According to the Regulation 28 of Securities Contracts (Regulation) (Stock Exchanges and Clearing Corporations) Regulations, 2018, What are the three v...
