Question
The following is the subscription information of a
sports club for the year ending 31.03.2023:Â Â What is the total subscription received during the year 2022-23?Solution
Subscription for 2022–23 (for 80 members) 80 × 1,200 = ₹96,000 should relate to this year. This ₹96,000 is split into: Part received last year as advance → ₹10,000 Part not yet received (outstanding 31-03-2023) → ₹20,000 The rest must have been received this year for 22–23. So, received this year for 22–23 = 96,000−10,000−20,000=66,000 2. Add receipts for other years that also came in this year Previous year’s outstanding (31-03-2022) = ₹14,000 → received in 22–23 Advance received in 22–23 for next year (31-03-2023) = ₹9,000 3. Total subscription received during 2022–23 66,000 (for 22–23)+14,000 (for 21–22)+9,000 (for 23–24) = 89,000
28(4/5) + 52(1/2) × 8(2/7) - 11(1/5) = ? + 6(1/5)
What is (0.08% of 0.008% of 8)1/9 ?
3% of 3000 x ?% of 2000 = 3600
(62 - 52 ) % of 800 = 22 X √?
1500 ÷ 15 + 1000 ÷ √100 + ? = 250 * 3
√(24 × 5 ÷ ?) × 4 = 56 + 34 – 10
242 + 18 × 8 – ? = 356
1.25 × 36 + 2.75 × 40 = ? × 3.1
4.004 + 5.7(2.5 – 0.5) =?
48 ÷ 6 × √25 + 13 × 8 = ?