Question

If the mean of 3, 4, 9, 2k, 10, 8, 6 and (k + 6) is 8,

1. Using the mean and mode conditions, solve for k and p. 2. Substitute into k 2p to get the answer.

and mode of 2, 2, 3, 2p, (2p + 1), 4, 4, 5 and 6 (p is a natural number) is 4, then the value of (k – 2p) is :

B 1

C 2

D 3

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Solution