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    Question

    The average of 28 numbers is 50. The average of the

    first 16 numbers is 55, while the average of the last 13 numbers is 45. If the 16th number is removed, what will be the average of the remaining 27 numbers, rounded to one decimal place?
    A 68.5 Correct Answer Incorrect Answer
    B 14.8 Correct Answer Incorrect Answer
    C 38.5 Correct Answer Incorrect Answer
    D 49.4 Correct Answer Incorrect Answer

    Solution

    ATQ, Sum of 28 numbers = 50 ├Ч 28 тЗТ 1400 Sum of first 16 numbers = 55 ├Ч 16 тЗТ 880 Sum of last 13 numbers = 13 ├Ч 45 тЗТ 585 Let the 16th number be x Sum of 28 numbers = Sum of first 16 numbers + Sum of last 13 numbers - 16th number тЗТ 1400 = 880 + 585 - x тЗТ 1400 = 1465 - x тЗТ x = 1465 - 1400 тЗТ x = 65 Sum of remaining numbers = 1400 - 65 тЗТ 1335 Remaining numbers = 27 Average of remaining numbers = 1335 / 27 тЗТ 49.4 тИ┤ The average of the remaining numbers (correct to one decimal place) is 49.4

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