Question
A sum of ₹10,000 is invested in two parts: one part at
12% per annum simple interest and the other part at 8% per annum simple interest. After 3 years, the total interest earned is ₹3,000. Find the amount invested at 12%.Solution
Let the amount invested at 12% be x, and the amount invested at 8% be (10,000 - x). Interest from the first part = (x × 12 × 3) / 100 = 0.36x. Interest from the second part = ((10,000 - x) × 8 × 3) / 100 = 0.24(10,000 - x). Total interest = ₹3,000. 0.36x + 0.24(10,000 - x) = 3,000. 0.36x + 2,400 - 0.24x = 3,000. 0.12x = 600, so x = ₹5,000. Correct option: b
14, 17, 23, 32, ?, 59
3, 8, 27, 124, ?
If series II follows the same sequence pattern as series I shown below, determine the value of 'p'.
Series I: 3, 4, 9, 34, 159, 784
Se...
12, 13, 27, 82, 329, ?
166 156 136 ? 66 16
11 6 7 12 26 ? 205.5
What value should come in the place of (?) in the following number series?
4, 10, 22, 46, ?, 190
1290, 1225, 1175, ?, 1112, 1095, 1085
230 192 172 ? 122 100
...150, 158, 131, 195, 70, ?
