Question
A sum of ₹10,000 is invested in two parts: one part at
12% per annum simple interest and the other part at 8% per annum simple interest. After 3 years, the total interest earned is ₹3,000. Find the amount invested at 12%.Solution
Let the amount invested at 12% be x, and the amount invested at 8% be (10,000 - x). Interest from the first part = (x × 12 × 3) / 100 = 0.36x. Interest from the second part = ((10,000 - x) × 8 × 3) / 100 = 0.24(10,000 - x). Total interest = ₹3,000. 0.36x + 0.24(10,000 - x) = 3,000. 0.36x + 2,400 - 0.24x = 3,000. 0.12x = 600, so x = ₹5,000. Correct option: b
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a) Oxygen scavenger
b) Carbon Dioxide scavenger
c) Ethylene scavenger
d) Moisture remover
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Viscosity is a property of
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