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ATQ,
Let the length of shorter train (train ‘X’) be ‘x’ meter. So, length of the longer train (train ‘Y’) = (x + 180) meters ATQ; {(162 + 108) × (5/18)} = {(x + x + 180)/12} Or, (75 × 12) = (2x + 180) Or, (900 – 180) = 2x Or, (720/2) = x So, x = 360 m Length of shorter train (train ‘X’) = 360 m Length of longer train (train ‘Y’) = 540 m So, time taken by the longer train to cross a tree = {540/(162 × 5/18)} = (540/45) = 12 seconds
Statement: H > G = M > S ; G `>=` T > L; M `<=` F < U
Conclusion: I. L > M II. G < U
...Statements: A ≤ E, P < Q > X, E = P, Y ≥ Z = A
Conclusions:
I. Q > E
II. E < X
Statements: U > H ≥ W; S > T ≥ B; S < H; C ≤ D = U
Conclusions:
I. D > B
II. T < U
III. W ≤ D
Statements : R < O ≤ P < Q; M < L ≤ N > O; S < Q ≤ K
Conclusions:
I. M < K
II. N > R
III. O < S
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and then...
Statements: Z % Y; X # W; U % V; W & V; Y @ X
Conclusions:
I. U @ X �...
Statements: U ≤ T < V; W < V; S = T < R; X < W = Y < Z
Conclusions:
I. R > U
II. X < S
III. T < Z
Statements: V > R ≥ W < Z; X ≤ W; U < R ≤ Y
Conclusions:
I. X < Z
II. W < Y
III. Z > U
Statements: T < Q ≥ L; W < Q ≥ E; E < S
Conclusions:
I. T < S
II. S > Q
III. E < L
Statements: I > D > J < E; C > J > K; G < K > A
Conclusions:
I. I > A
II. G < E
III. D ≥ K
