Question
Pipe ‘X’ can fill a tank in 15 hours, while pipe
‘Y’ can fill the same tank in 20 hours. If both pipes are opened simultaneously, how long will it take to fill 70% of the tank?Solution
ATQ,
Let capacity of the tank be 60 litres {LCM of (15 and 20)} Efficiency of pipe ‘X’ = (60/15) = 4 litres/hours Efficiency of pipe ‘Y’ = (60/20) = 3 litres/hour Required time = {(0.70 × 60)/(4 + 3)} = 6 hours
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