Question
A is twice as old as B. B is 1/3 as old as C. The sum of
ages of A, B, and C is 42 years. Find the sum of the ages of A and B.Solution
ATQ, A is twice as old as B: So, A=2B. B is one-third of C's age: So, B = (1/3)C or C=3B. The total of their ages is 42: So, A+B+C=42. Now, substitute the relationships into the total equation: A=2B and C=3B, so we get: 2B+B+3B=42 This simplifies to 6B=42, so B=7. Then, A=2×7=14 and C=3×7=21. The sum of A and B's ages is = 14+7 = 21 So, the sum of the ages of A and B is 21 years.
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