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    Question

    A is twice as old as B. B is 1/3 as old as C. The sum of

    ages of A, B, and C is 42 years. Find the sum of the ages of A and B.
    A 21 years Correct Answer Incorrect Answer
    B 23 years Correct Answer Incorrect Answer
    C 15 years Correct Answer Incorrect Answer
    D 12 years Correct Answer Incorrect Answer

    Solution

    ATQ, A is twice as old as B: So, A=2B. B is one-third of C's age: So, B = (1/3)C or C=3B. The total of their ages is 42: So, A+B+C=42. Now, substitute the relationships into the total equation: A=2B and C=3B, so we get: 2B+B+3B=42 This simplifies to 6B=42, so B=7. Then, A=2×7=14 and C=3×7=21. The sum of A and B's ages is = 14+7 = 21 So, the sum of the ages of A and B is 21 years.

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