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Radius (r) of given cylindrical wooden block = 3/2 cm (because Diameter = 2*radius) Length (h) = 20cm The volume of the block = πr²h = π *(3/2)²* (20) = 45 π Now we need to find max number of pieces of 1 cm in diameter. So, radius = 1/2 cm, length = 20cm So, volume of the required block = πr2h = π*(1/2)2*(20) = 5π So, max pieces = 45 π /5 π = 9 pieces.
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